Due to the nature of this problem do not use rounded interme

Due to the nature of this problem, do not use rounded intermediate values in your calculations—including answers submitted in WebAssign.

Find the currents flowing in the circuit in the figure below. (Assume the resistances are R₁ = 6 ?, R₂ = 20 ?, R₃ = 15 ?, R₄ = 10 ?, r₁ = 0.25 ?, r₂ = 0.5 ?, r₃ = 0.25 ?, and r₄ = 0.5 ?.)

Solution

From Kirchoff\'s Junction rule

I₁ = I₂+I₃

I₁-I₂-I₃=0------------------------------------------------1

Applying Kirchoff\'s loop rule in left loop abefa

18-(6+0.25+10)I₁-(20+0.5)I₃+3=0

16.25I₁+20.5I₃ =21----------------------------------2

Applying Kirchoff\'s loop rule in right loop bcdeb

-(15+0.25+0.5)I₂+12-24+(20+0.5)I₃-3=0

-15.75I₂+20.5I₃=15-----------------------------------3

Solving 1,2 and 3 we get

I₁=0.4976 A

I₂=-0.1324 A

I₃=0.63 A