Homework SourseWith the parents of cross Bb x bb what is the probability of
With the parents of cross \"Bb x bb\", what is the probability of that 2 children will have brown eyes and 2 children will have blue eyes (any order)?
brown eyes(B) = dominant, blue eyes (b) = recessive
With the parents of cross \"Bb x bb\", what is the probability of that 2 children will have brown eyes and 2 children will have blue eyes (any order)?
brown eyes(B) = dominant, blue eyes (b) = recessive
With the parents of cross \"Bb x bb\", what is the probability of that 2 children will have brown eyes and 2 children will have blue eyes (any order)?
brown eyes(B) = dominant, blue eyes (b) = recessive
Solution
Parents: Bb X bb
Gametes: B, b, b, b
F1 : Bb, Bb, bb, bb
1----------1 1----------1
Brown Blue
Probability that the children has brown eyes = 2 / 4 = 1/2 = 0.5 = 50%
Probality that the children has blue eyes = 2 / 4 = 1/2 = 0.5 = 50%
![With the parents of cross \](/WebImages/16/with-the-parents-of-cross-bb-x-bb-what-is-the-probability-of-1028761-1761532922-0.webp "With the parents of cross \")
