A company makes 3 types of cable Cable A requires 3 black 3
A company makes 3 types of cable. Cable A requires 3 black, 3 white, and 2 red wires. Cable B requires 1 black, 2 white, and 1 red wires. Cable C requires 2 black, 1 white, and 2 red wires. They used 100 black, 110 white and 80 red wires. How many of each cable were made?
Solution
Sol)
Let a = no. of A cables
Let b = no. of B cables
Let c = no. of C cables
:
Write an equation for each color wire
black: 3a + b + 2c = 100
white: 3a + 3b + c = 110
red::: 2a + b + 2c = 80
By solving above equation we get
a=20
b=12
c=14
Hence
a = no. of A cables =20
b = no. of B cables=12
c = no. of C cables=14
:
