In the figure a metal wire of mass m 249 mg can slide with

In the figure, a metal wire of mass m = 24.9 mg can slide with negligible friction on two horizontal parallel rails separated by distance d = 1.44 cm. The track lies in a vertical uniform magnetic field of magnitude 56.7 mT. At time t = 0 s, device G is connected to the rails, producing a constant current j = 9.36 mA in the wire and rails (even as the wire moves). At t = 59.5 ms, what are the wire\'s (a) speed and (b) direction of motion?

Solution

a)

The Magnetic force on the wire is

F=BId

Since

V=at =(F/m)*t =BIdt/m

V=(56.7*10^-3)(9.36*10^-3)*(0.0144)(59.5*10^-3)/(24.9*10^-3)

V=1.826*10^-2 m/s

b)

Direction is to the left i.e away from the generator .