During a certain 15 hour period the temperature at time t me

During a certain 15 hour period, the temperature at time t (meausred in hours form the start of the period) was T(t)= 46+4t-(1/3)t^2 degrees. What was the average temperature during that period?

1/15 ?(46+4t-(1/3)t^2)

1/15 (46t+2t^2-(1/6)t^3)

1/15 (46(0)+2(0)^2-(1/6)(0)^3)=0

Solution

you made a mistake at the second line:

int (1/3) t^2 = (1/9) t^3

not (1/6) t^3