Find the value of x in each of the following logx 81 4 righ

Find the value of x in each of the following: log_x 81 = 4 rightarrow x = log_4 x = -5 rightarrow x = log_x 4 = 1/3 rightarrow x =

a) logx(81) = 4

Use the lwas of logaritm : loga(x) = b ----> x = a^b

So, 81= x^4

(3)^4 = x^4

x = 3

b) log4(x) = -5

x = 4^-5

x = 1/1024

c) logx(4) = 1/3

4 = x^1/3

Take cube on both sides

4^3 = (x^1/3)^3

x = 64