A 420 turn solenoid of length 350 cm and radius 320 cm carri

A 420 turn solenoid of length 35.0 cm and radius 3.20 cm carries a current of 4.80 A. Find the following.

(a) the magnetic field strength inside the coil at its midpoint
mT

(b) the magnetic flux through a circular cross-sectional area of the solenoid at its midpoint
T · m²

a) For a solenoid .. B = N i / L

B = (4^-7) x 420 x 4.80 / 0.35m .. .. . B = 7.24 mT

b) Flux, = B x A .. 7.24T x (0.032m)² .. .. = 0.0232 T.m²