A threephase 460V 60Hz system supplies power to the followin

A three-phase, 460-V, 60-Hz system supplies power to the following diode bridge rectifier. The load is a 100-ohm resistor. Find: average load voltage average load current average current that each diode must conduct peak reverse voltage to which each diode is subjected average load power.

Solution

VRMS=460 VOLTS

f=60 HZ

RL=100 OHS

AVERAGE LOAD VOLTAGE(vo)=(3*1.73*Vm)/3.14=(3*1.73*1.414*460)/3.14=1075.98 volts

average load current (io)=vo/100=1075.98/100=10.7598 amps

average load power(po)=vo*io=1075.98*10.7598=11577.3296 watts.

average current that each diode must conduct=io/3=10.7598/3=3.5866 amps.