Write a JAVA program to display following pattern You first

Write a JAVA program to display following pattern. You first need to read number of rows and columns and based on it your patter should be. For example, if you road 5 as row value and 4 as column value then, your pattern should look like: If you read 10 as row value and 5 as column value then, your pattern should look like: Write a JAVA program to read a number from user and then find out all prime numbers up to that number. For Example, if user enters 10, then your program should show: The prime number up to 10 are: 2, 3, 5, 7 if user enters 0, then your program should show: The prime number up to 10 are: 2, 3, 5, 7, 11, 13, 17, 19

Solution

1 : Program

import java.util.Scanner;
public class pattern
{
  
public static void main(String args[])
{
int m,n;
Scanner in = new Scanner(System.in);
System.out.println(\"Enter the number of rows and columns of matrix\ \");
m = in.nextInt();
n = in.nextInt();
for(int i=1;i<=m;i++)
{
for(int j=1;j<=n;j++)
{
if(j%2==1)
{
System.out.print(\"*\\t\");
}
else
{
System.out.print(\"-\\t\");
}
}
System.out.print(\"\ \");
}
}
}

2 Program :

import java.util.Scanner;

public class primenumber {
public static void main(String[] args)
{
int n,p;
Scanner in = new Scanner(System.in);
System.out.println(\"Enter a number\ \");
n = in.nextInt();
System.out.println(\"The prime numbers upto \" + n + \" are\");
for(int i=2;i<n;i++)
{
p=0;
for(int j=2;j<i;j++)
{
if(i%j==0)
p=1;
}
if(p==0)
  
System.out.print(i+\"\\t\");
}
}
  
}