Smiar to tho previals paye guastar but Hts tus yox ore a hug
Solution
SOLUTION 1:
This is a not \"closed system,\" meaning water will not \"move out\" of the system.
Thus h0 = h1
SOLUTION 2:
Using the Archimedes principle of buoyancy.
Let’s say that the mass of the boat is M and the mass of the anchor is m. The density of water is w and the density of the anchor is a. When the anchor is in the boat, the volume of water displaced is
V1 = (M + m) / w = M / w + m / w
and when the anchor is in the water, the volume of water displaced is
V2 = M / w + m / a
It’s obviously that
a > w
then
V1 > V2
Thereby, the water level falls when the yacht drops anchor overboard.
DN<Do
