Given the morning traffic data in Table 2 identify which hou

Given the morning traffic data in Table 2, identify which hour is the morning peak hour. If AADT is equal to 10,600 vehicles, find K factor for the morning peak hour and the PHF within the peak hour. (Hint: the peak hour doesn\'t have to begin on the hour) Table 2: Morning Traffic Data End 7:15 AM 7:30 AM 7:45 AM 8:00 AM Count Period Begin Number of Vehicles 7:00 AM 7:15 AM 7:30 AM 7:45 AM 8:00 AM 8:15 AM 8:30 AM 302 309 320 342 8:15 AM436 1 4 462 502 8:30 AM 8:45 AM 9:00 AM 9:15 AM 9:30 AM 9:45 AM 10:00 AM 7 489 447 450 402 360 88:45 AM 9:00 AM 9:15 AM 9:30 AM 9:45 AM 9 10 12

Solution

1. Morning peak hour-- 8:15AM to 9:15AM

2. Peak hour volume= 462+502+489+447=1900 vehicles

Within this peak hour, 8:30 AM TO 8:45AM has peak 15 min volume which is 502 vehicles

So, PHF = 1900/4*502=0.9462~0.95

3. K factor for morning peak hour= DHV/AADT

Where DHV ,design hourly volume= 4* Peak hour volume/PHF = 4*502/0.95=2120 vehicles

So, K factor for morning peak hour =DHV/ AADT

=2120/10600 = 0.2