for part a the pull force asked why we find the work not the

for part (a) the pull force asked why we find the work not the force ?

please help me

http://www.chegg.com/homework-help/questions-and-answers/piston-cylinder-device-contains-002-m3-hydrogen-300-k-diameter-13-cm--piston-assumed-weigh-q13267451

Area A = 3.14/4*0.13^2 = 0.0133 m^2

Pressure due to force = F / A = F / 0.0133

Equating pressure on both sides of piston, 42 + F / 0.0133 = 96

F = 0.716 kN = 716 N

for part (a) the pull force asked why we find the work not the force ? please help me http://www.chegg.com/homework-help/questions-and-answers/piston-cylinder-d

for part a the pull force asked why we find the work not the

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