143285 points Previous Answers serpset9 26p 035 nva 8100 S

. 1.43/2.85 points | Previous Answers serpset9 26.p 035 nva 8/100 Submissions Used My Notes Ask Your Teac Two identical parallel-plate capacitors, each with capacitance 13.5 F, are charged to potential difference 48.0 V and then disconnected from the battery. They are then connected to each other in parallel with plates of like sign connected Finally, the plate separation in one of the capacitors is doubled. (a) Find the total energy of the system of two capacitors before the plate separation is doubled. (b) Find the potential difference across each capacitor after the plate separation is doubled. Did you accidentally divide or take the inverse in your calculation? V (c) Find the total energy of the system after the plate separation is doubled. 062 Your response differs from the correct answer by more than 10%. Double check your calculations.) (d) Reconcile the difference in the answers to parts (a) and (c) with the law of conservation of energy. Positive work is done by the agent pulling the plates apart. Negative work is done by the agent pulling the plates apart. No work is done by pulling the agent pulling the plates apart. Submit Answer Save Progress Practice Another Version

Solution

a) 0.031 j

b) 64 v

c) 0.041 j

d) positive work is done by pulling the plates apart.