f x x2 then f x the tangent to the graph of f through th

f (x) = x^2 then f \' (x) = ? the tangent to the graph of f through the point (1,1) has the slope .......? and the y-intercept ........? it intercepts with the x-axis at x = ?

f(x)= x^2

f\'(x)= 2x

at(1,1)
slope =2 x= 2

so, equation of tangent is
y-1 = 2(x-1)
=> y= 2x-1
so, y-intercept is -1

put y=0 => x=0.5
=> x-intercept = 0.5
meets x-axis at (0.5,0)

$f (x) = x^2 then f \' (x) = ? the tangent to the graph of f through the point (1,1) has the slope .......? and the y-intercept ........? it intercepts with the$

f x x2 then f x the tangent to the graph of f through th

Solution

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