find the vertical horizontal and oblique asymptotes Txx2x416

find the vertical, horizontal and oblique asymptotes T(x)=x^2/x^4-16

Solution

T(x) = x^2/( x^4 -16)

Vertical asymtotes: equate denominator to zero.

x^4 -16 =0 ---->( x^2 -4)(x^2 +4) =0

x^2 = 4 -----> x= 2 and x=-2 are vertical asymtotes

Horizontal asymtotes: Since the degree is greater in the denominator than in the numerator, the y-values will be dragged down to the x-axis, and the horizontal asymptote is therefore \"y = 0\".

y = 0