Assignment Make Connections The Hardy Weinberg Principle and

Assignment Make Connections: The Hardy Weinberg Principle and the Inheritance of Alleles previous 50 28 Part B The Hardy-Weinberg Principle In Part A you looked at a single genetic oross involving two parents of genotype Rr lmagine now hat instead of a single Gametes for each generation are drawn at random from mating, you consider al the matings that occur in a population and al he offspring that are produced the gene pool of the previous generation: The figure at right shows a population of fowers with Mo alleles for color, ared alele CR and a white alele Cw.The allele 20% c\" (4- 0.2) 80% (P 0.8) frequencies across the entire population are 80% c and 20% cw.In other words: The frequency of the CR alele, caled p is08. The frequency of the Cw allele, called q is 02. Mthe population is not evolving, then the population is said to be in Hardy-Weinberg equilibrium, In this case, the Hardy- Weinberg principle tells us that offspring inherit aleles as if they were drawn from the gene pool at random. This means that The proportion of individuals with genotype c\'RcR is expected to be The proportion of individuals with genotype c icin isexpected to be 2pg. (80%) The proportion of individuals with genotype cWcWis expected to be q 64% (v?) 16% (PN) Furthermore,ifa population is in Hardy Weinberg equilibrium, the allele fequencies (pand q and the genotype fequencies eggs stay the same from one generation to the next If the gametes come together at random, the genotype frequencies of this generation are in Handy-Weinberg equlibrium: Gametes of this generation: 64% 16% CA from CRC (from CRCW 80% Ce 0.8 wp plants) 4% cw 16% cm (from Caca (from CRC 20% Cu 0.2 g With random mating, these gametes will result in the same mix of in the next generation Drag the percentages on the left to answer the questions on the right. Percentages may be used once, more than

Solution

1. there would two types of gamemte one with C^R or C^W so chances are equal that is 50%

2. same like first

3. C^RC^R is the frequency of p² so according to previous slide p=0.8 then p2=0.64 that is 64 % would be C^RC^R

4. C^WC^W is the frequency of q² so according to previous slide q=0.2 then p2=0.04 that is 4 % would be C^WC^W

5. C^RC^W is the frequency of 2pqso according to previous slide p=0.8 & q=0.2 then 2pq=0.32 that is 32 % would be C^RC^W

6. As they are in equlibrium the frequency would same as before C^R=0.8 (80 %) and C^W=0.2 (20 %)