A uniform magnetic field passes through a horizontal circula

A uniform magnetic field passes through a horizontal circular wire loop at an angle 18.1degree from the normal to plane of the loop. The magnitude of the magnetic field is 2.95 T, and the radius of the wire loop is 0.290 m. Find the magnetic flux through the loop. Number The magnetic flux depends on the magnitude of the magnetic field, the area enclosed by the loop, and the angle between the magnetic field and the normal (or perpendicular) to the plane of the loop.

Solution

magnetic flux = B.dA

Phi = B*A*cos theta

theta = 18.1 deg

phi = 2.95*3.14*0.29^2*cos 18.1 deg = 0.74 Wb