Solve the equation in the interval 0 360 Give solutions to t

Solve the equation in the interval [0°, 360°). Give solutions to the nearest tenth, if necessary.

sin² - sin - 12 = 0

Select one:

a. {45°}

b. {45°, 315°}

d. {45°, 135°}

Solution

sin2 - sin - 12 = 0

sin2 - sin = 12

range of sine function is [-1,1]

so sin2 - sin = 12 is not possible

so no solution