Please help me with this ASAP ThanksSolutionCheck this once

Solution

Check this once might be weather is right or wrong

_max = V²/(4*R₁) = 100²/(2*4*5) = 250 mW

The reactive power: first the current:

I = V / (R₁ + R₂ + j(wL – 1/wC)) = 100/10 = 10 mA

Q = - I²/2 * X_C = - 50*2 = - 100 mvar

c.) The load voltage in the case of maximum power transfer:

V_L = I*(R₂ + 1/ (j w C ) = 10*(5-j/(1*0.5)) =50 – j 20 = 53.852 e ^{-j 21.8°} V

and the time function: v(t) = 53.853 cos (wt – 21.8°) V