Ten kilograms of R134a fill a 1595 m3 weighted pistoncylinde

Ten kilograms of R-134a fill a 1.595 m^3 weighted piston-cylinder device (because the piston is \"weighted\", this makes the system constant pressure) at a temperature of -26 degree C. The container is now heated until the temperature is 100 degree C. Determine the final volume of the R-134a.^1

Solution

From R134a properties table

At -26.4 c saturated pressure is 100kpa is the pressure inside the container because the specific volume is 1.595/10 = 0.1595 m3/kg which is in between Vf and Vg at -26.4c

Now at same pressure temperature is changed to 100 c

Now from superheated tables

Specific volume is 0.3014m3/kg

Volume = 0.3014*10=3.014 m3

 Ten kilograms of R-134a fill a 1.595 m^3 weighted piston-cylinder device (because the piston is \

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