Find the area of the triangle having the indicated angle and
Find the area of the triangle having the indicated angle and sides. C=84 30\', a=16, b=20
Solution
angle C = 84030\'
10 = 60min( 60\')
1\' = ( 1/60)0
angle C = 84030\' = 840 + ( 30* 1/60) 0
= 84.50
area = (1/2)*a*b*sin C
= (1/2)*16*20*sin( 84.5)
= 159.26 sq units
