Homework SourseThe torsion BAR shown is designed to hold 30000 in ib of tor
The torsion BAR shown is designed to hold 30.000 in ib of torque per degree of twist Given G = 11.4x10^6psg L=12\" determine the rep\'a dimeter of the bar ![The torsion BAR shown is designed to hold 30.000 in ib of torque per degree of twist Given G = 11.4x10^6psg L=12\](/WebImages/16/the-torsion-bar-shown-is-designed-to-hold-30000-in-ib-of-tor-1029737-1761533539-0.webp "The torsion BAR shown is designed to hold 30.000 in ib of torque per degree of twist Given G = 11.4x10^6psg L=12\")
Solution
Second moment of area of the cross section of cylinder,I = pi r ^4 / 2
but T = I G (theta) / l
80,000in lbs = 1.57*11.4*10^6 psi * r^4 / 12 inch =>
921.69 Nm = 4.04*10^11 r^4
r = 0.69 cm
d = 1.38cm
