The first part of the 660mile journey was by car at 30 MPH T

The first part of the 660-mile journey was by car at 30 MPH. The second part was by bus at 60 MPH. If the total time was 14 hours, what was the distance traveled by bus?

Solution

Let x=distance travelled by bus
Then 660-x=distance travelled by car
We\'ll make use of the formula Distance(d)=rate(r) x time(t) or d=rt
Now we know that the time it took the car (d/r) which was (660-x)/30 plus the time it took the bus (d/r) which was x/60 equals 14 hrs so our equation to solve is:
(660-x)/30+x/60=14 multiply both sides by 60 to get rid of the fractions:
2(660-x)+x=14(60)=840 simplifying:
1320-2x+x=840 collecting like terms:
-x=-1320+840=-480
x=480 miles distance travelled by bus
660-x=660-480=180 miles distance travelled by car

ck
180/30+480/60=14
6+8=14
14=14
Hope this helps.