find the exact value of sinalphabeta if sin alpha 35 and si

find the exact value of sin(alpha+beta) if sin (alpha) = -3/5 and sin (beta) =-12/13, with alpha in QIII and beta in QIV

sin (alpha) = -3/5 => cos(alpha) = -[(5²-3²)]/5 =-4/5

sin (beta) =-12/13 =>cos(beta) = [(13²-12²)]/13 =5/13

sin(alpha+beta) =sin(alpha)cos(beta) +cos(alpha) sin(beta)

sin(alpha+beta) =(-3/5)(5/13) +(-4/5)(-12/13)

sin(alpha+beta) =(-15/65) +(48/65)

sin(alpha+beta) =(33/65)