6x217x7 divide x2 your answer should give the quotient and

(6x^2+17x+7) divide ( x+2). your answer should give the quotient and the remainder.

we have (6x^2+17x+7) and divisor (x+2).

Using long divison method

first we need to multiply our divisor by a term so that the first term of product should match the first term of dividend.

so we multiply our divisor by \"6x\" to get 6x^2 as the first term. (6x *(x+2) = 6x^2 + 12x ) and we write \"6x\" in the quotient

divisor dividend quorient

x+2 6x^2+17x+7 6x + 5

6x^2+12x now we reverse the sign of the product (6x^2 +12x) as (-6x^2 -12x) and add them

- - so that we can eliminate the first term (6x^2 of the dividend and -6x^2 of the product gets cancel)

we get \"5x\" from 17x -12x and then we copy down 7 with \"5x\" term

5x + 7 now in order to cancel 5x we need to multiply divisor by \"5\" and we write \"+5\" in quotient

5x +10

- - we again change the sign and cancel the terms

we add (5x+7) and (-5x -10) we get \"-3\" now we cannot multiply our divisor witha linear term to get \"-3\"

so we get \"-3\" this is our remainder and (6x+5) as quotient (ANSWER)

divisor dividend quorient

x+2 6x^2+17x+7 6x + 5

6x^2 +12x

- -

5x +7

5x +10

- -

-3 remainder