A company wants to determine the sample size necessary to de

A company wants to determine the sample size necessary to determine its mean ordering lead time within 2 days at 99% confidence. If the variance of the lead times is 49, what size sample should it take?
A company wants to determine the sample size necessary to determine its mean ordering lead time within 2 days at 99% confidence. If the variance of the lead times is 49, what size sample should it take?

Solution

Confidence Interval CI = 99%

z value = 2.576   ( for 99% CI )

X = 2

Variance = 49 , therefore

Standard Deviation SD = sqrt (49) = 7

z = X / (SD/sqrt(n))

=> 2.576 = 2/(7/sqrt(n))

=> 2.576 = (2*sqrt(n) ) / 7

=> 2.576 * 7 = (2*sqrt(n) )

=> sqrt(n) = (2.576 * 7) / 2

=> sqrt(n) = 9.016

=> n = 81.3 ~ 81 Answer

A company wants to determine the sample size necessary to determine its mean ordering lead time within 2 days at 99% confidence. If the variance of the lead tim

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