5Which one of the following cannot be an alternative hypothe

5.Which one of the following cannot be an alternative hypothesis H(a)?

Select one:

a. p > 0.3

b. p 0.3

c. p < 0.3

d. p 0.3

Questions 6 to 10 are related. Based on a random sample of n=15 observations, we have obtained a sample mean of x(bar)=1050. The goal is to test:

H(0): 1000 and

H(a): >1000

6.Assume that x is normally distributed with =150. What is the standard error ( (x bar) )? Rounded to two decimal places.

Select one:

a. 150/15 = 10

b. 150/15 = 38.73

c. None of the above

7.To conduct the test as given in question 6), which test statistics, is appropriate?

Select one:

a. t

b. z

c. F

d. None of the above

8.Building on question 7), what is the value of the test statistics? Rounded to two decimal places.

Select one:

a. (1050-1000)/38.73 = 1.29

b. (1050-1000)/10 = 5

c. None of the above

9.Using =0.1, what is the critical value (use Excel) for testing the hypotheses in question 6)? Rounded to two decimal places.

Select one:

a. –T.INV(0.1, 14) = 1.35

b. –NORM.S.INV(0.1) = 1.28

c. –T.INV(0.05, 14) = 1.76

d. -NORM.S.INV(0.05) = 1.64

10. using correct answers for questions 8) and 9),

Select one:

a. We reject H(0) because the test statistics value is less than the critical value

b. None of the above is correct

c. We reject H(0) because the test statistics value is greater than the critical value

Question 11-14 are related. Based on the random sample of n=800 observations, we have obtained a sample proportion p(bar) =0.44. The goal is to test:

H(0): p0.48

H9a): p<0.48

11.What is the standard error ((p))? Rounded to four decimal places.

Select one:

a. (0.48*0.52)/800 = 0.0003

b. ((0.48*0.52)/800) = 0.0177

c. None of the above

12.What is the value of the test statistics? Rounded to two decimal places.

Select one:

a. z=(0.44-0.48)/0.0003 = -133.33

b. z=(0.44-0.48)/0.0177 = -2.26

c. None of the above

13.Using =0.05, what is the critical value (use Excel) for testing the hypotheses in question 11)? Rounded to two decimal places.

Select one:

a. –NORM.S.INV (0.05) =1.64

b. NORM.S.INV (0.05) = -1.64

c. –NORM.S.INV(0.025) = 1.96

d. NORM.S.INV(0.025) = -1.96

14.Using correct answers for questions 12) and 13),

Select one:

a. We reject H(0)because z is greater than the critical value

b. We reject H(0)because z is less than the critical value

c. None of the above is correct

15.We have n=15, x(bar) =10, s=4, and (1-)=0.99. We wish to obtain the 99% confidence interval estimate of . What is the margin of error (rounded to two decimal places)?

16.

Which one of the following is a point estimator?

Select one:

b. x (bar)

17.

When the population standard deviation () is NOT known and we wish to estimate , the margin of error is obtained as

Select one:

a. z_/2 × s/n

b. t_/2 × s/n

18.

When the population standard deviation () is known and we wish to estimate , the margin of error is obtained as

Select one:

a. z_/2 × s/n

b. t_/2 × s/n

c. z_/2 × /n

19.

We have n=15, x(bar)=10, s=4 and (1-)=0.99. Using Excel and after rounding to two decimal places, the critical value, t_/2, is

Select one:

a. 2.98

b. 1.76

c. 2.14

20.

We have n=15, x =10, s=4 and (1-)=0.99. The standard error of x (rounded to two decimal places) is

Select one:

a. 0.27

b. 1.03

c. 7.5

21.

The sample proportion, p(bar) = 0.25 and n=36. The standard error of p(bar) (rounded to two decimal places) is given by

Select one:

a. ((0.25*0.75)/36) = 0.07

b. 0.25/36 = 0.04

c. (0.25*0.75) = 0.43

22.

Suppose (1-)=0.95 and n = 20. The critical value t_/2, can be obtained in Excel using

Select one:

a. –T.INV(0.025, 19)

b. –T.INV(0.05, 19)

c. –T.INV(0.1, 19)

23.

Suppose (1-)=0.9. The critical value, z_/2 , is obtained in Excel using

Select one:

a. –NORM.S.INV(0.05)

b. –NORM.S.INV(0.1)

c. –NORM.S.INV(0.2)

24.

Given the sample proportion (p ) and sample size, n, we wish to obtain the confidence interval estimate of the population proportion (p). The margin of error of the confidence interval estimate is obtained as

Select one:

a. z(/2) ×((p(bar)(1-(p(bar))))/n)

b. z(/2) ×((p(1-p))/n)

5.The Following cannot be an alternative hypothesis H(a)

b. p 0.3

6.The standard error is:

b. 150/15 = 38.73

7.The appropriate test statistic is:

b. z

8.The test statistic is: a. (1050-1000)/38.73 = 1.29

9. b. –NORM.S.INV(0.1) = 1.28

10. c. We reject H(0) because the test statistics value is greater than the critical value