2 fing T and PSolutioni think 40 in degrees 1Tsin40o4 T4sin4

2/ fing T and P

Solution

i think 40 in degrees

1)Tsin40o=4

T=4/sin40o

T=4/0.643

T=6.223

2)Tsin30+Pcos30 =5,2T-4pcos120=11

T(1/2)+P(3 /2) =5

T +P3 =5*2

T +P3 =10

2T +P23 =20-------------->(1)

2T-4Pcos120=11

2T-4Pcos(90+30)=11

2T-4P(-sin30)=11

2T-4P(-1/2)=11

2T+2P=11---->(2)

(1)-(2)

2T +P23 -2T-2P=20-11

P(23-2)=9

P=9/(23-2) =6.147

2T+2P=11

T=(11/2)-P

T=(11/2)-9/(23-2)

T=(11(3-1)-9)/(23-2)

T=(113 -20)/(23-2)

T=-0.647

so P=9/(23-2) ,T=(113 -20)/(23-2)

2/ fing T and PSolutioni think 40 in degrees 1)Tsin40o=4 T=4/sin40o T=4/0.643 T=6.223 2)Tsin30+Pcos30 =5,2T-4pcos120=11 T(1/2)+P(3 /2) =5 T +P3 =5*2 T +P3 =10 2

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