2 fing T and PSolutioni think 40 in degrees 1Tsin40o4 T4sin4
2/ fing T and P
Solution
i think 40 in degrees
1)Tsin40o=4
T=4/sin40o
T=4/0.643
T=6.223
2)Tsin30+Pcos30 =5,2T-4pcos120=11
T(1/2)+P(3 /2) =5
T +P3 =5*2
T +P3 =10
2T +P23 =20-------------->(1)
2T-4Pcos120=11
2T-4Pcos(90+30)=11
2T-4P(-sin30)=11
2T-4P(-1/2)=11
2T+2P=11---->(2)
(1)-(2)
2T +P23 -2T-2P=20-11
P(23-2)=9
P=9/(23-2) =6.147
2T+2P=11
T=(11/2)-P
T=(11/2)-9/(23-2)
T=(11(3-1)-9)/(23-2)
T=(113 -20)/(23-2)
T=-0.647
so P=9/(23-2) ,T=(113 -20)/(23-2)

