12 In Figure 3 below the arc AFE is a semicircle with center
12. In Figure 3 below the arc AFE is a semicircle with center C and Figure 3 radius IACl = ICE| = r. The inner arc is a semicircle with center C and radius IBC| = CD-s and the line DF is perpendicular to the line AE. If R is the region bounded by the two semicircles and the line segments AB and DE, show that Area(R)=-2 , where = IDPL ? 5NHAT SCRAMBLED WORD GAME by David L Hoyt and Jef Knurek Uriscrargbie nese iour Jumbies,r one Jeter.o. Bach square, to to n Tour orduriary words Mr. Bonsan ril need yo to stay.when., class is over CTFHE
Solution
Area (R) = Area of ( outer semicircle - inner semicircle )
= 1/2( r2) - 1/2( s2 )
= 1/2 .. (r2 - s2 )
= 1/2.. (DF)2
Area (R) = 1/2..a2
since we have from diagram
DF2 = EF2 - DE2
. DF2 = r2 - s2
.
