For the hydraulic jack illustrated in Figure P815 determine

For the hydraulic jack illustrated in Figure P8.15, determine:

            (a) the fluid pressure;

            (b) the ram force F.

Solution

(a) Fluid Pressure= F/A=200/(pi*10*10)=0.63694 pascal

Where F= force

Pi=22/7=3.14

A=area of cross section

(b) ram force F is:

By Pascal\'s Law,

P1=P2

(F1/A1)=(F2/A2)

(F/(pi*50*50))=(200/(pi*10*10))

F=200*50*50/100

F=5000 N