The length of a rectangle is 7 inches more than twice its wi

Solution

SOlution:

Givne

Let the length = l

let the width = b

The length of a rectangle is 7 inches more than twice its width.

l = 2b +7

area = 114

or l*b = 114

plug l =2b+7 in above

(2b+7)*b = 114

2b^2 +7b -114 = 0

solve this equation and we get

b = 6 and b = -19/2

since width cannot be negative hence we will consider only b = 6

therefore

l = 2*6+7 = 19

Hence

the width is 6 inches and length is 19 inches