Solve for x logx 5 log x 2 log 2x 6Solutionlogx5 logx2

Solve for x: log(x + 5) + log (x + 2) = log (2x + 6).

log(x+5) +log(x+2) = log(2x+6)

Use the log property : LogA +LogB = log(A*B)

So, Log(x+5)(x+2) = log(2x+6)

So, we can equate the aargumante inside the log on both sides:

(x+5)(x+2) = (2x+6)

x^2 +7x +10 = 2x +6

x^2 +5x +4 =0

factorise to solve for x:

x^2 +4x +x+4=0

x(x+4) 1(x+4) =0

(x+1)(x+4) =0

Solution : x= -1 , x= -4