for the planetary speed reducer shown below the arm is the i

for the planetary speed reducer shown below the arm is the input to the gear train. gear A is fixed (n=23teeth) and the internal gear C (55teeth) is connected to the output. if the input speed is at 100rpm. what is the output speed?

For the plunetary apeod reducer showa btw the wete is dre o pm, wha i the curpot shait speed to the s cocmecint so the urpaE the mput shak spend is 100

Solution

(R+S)*Ty=R*T_R+S*T_S

Where R: ring gear teeth (C), S: sun gear teeth (A), P: planet gear teeth (B), Ty: velocity of the planetary gear carrier, T_R: velocity of the ring gear, T_S: velocity of the sun gear.

In thise case T_S=0 because is fixed, so the velocity of ring gear is T_R=((R+S)/R)*Ty so T_R=((55+23)/55)*100=141.8 rpm