A refrigerator contains 6 apples 5 oranges 10 bananas 3 pear

A refrigerator contains 6 apples, 5 oranges, 10 bananas, 3 pears, 7 peaches, 11
plums, and 2 mangos.
a. Imagine you stick your hand in this refrigerator and pull out a piece of fruit
at random. What is the probability that you will pull out a pear?
b. Imagine now that you put your hand in the refrigerator and pull out a piece
of fruit. You decide you do not want to eat that fruit so you put it back into the
refrigerator and pull out another piece of fruit. What is the probability that the
first piece of fruit you pull out is a banana and the second piece you pull out is
an apple?
c. What is the probability that you stick your hand in the refrigerator one time
and pull out a mango or an orange?

Solution

a)

There are 44 fruits.

Thus, P(pear) = 3/44 = 0.068181818

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b)

Here,

P(banana) = 10/44
P(apple) = 6/44

P(banana then apple) = P(banana) P(apple) = (10/44)(6/44) = 0.030991736[ANSWER]

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C)

P(mango or orange) = P(mango) + P(orange) = 2/44 + 5/44 = 7/44 = 0.159090909 [ANSWER]