Use ft sect pi 1 to answer the following The period is Th

Use f(t) = sec(t + pi) + 1 to answer the following. The period is The fourths The function has a range of

Solution

As we know that

Range: (-infinity , -1] U [1 , +infinity) for y= secx

Here we   have y= sec( t+pi) +1

y-1 = sec( t+pi)

so we would have

(-infinity , -2] U [0, +infinity)