For part d the other options are do not reject or sufficient

For part d. the other options are do not reject or sufficient

According to a study by the American Pet Food Dealers Association, 69 percent of U.S. households own pets. A report is being prepared for an editorial in the San Francisco Chronicle. As a part of the editorial a random sample of 320 households showed 235 own pets. Does this data disagree with the Pet Food Dealers Association data? Use a 0.05 level of significance. State the null hypothesis and the alternate hypothesis. (Round your answers to 2 decimal places.) State the decision rule for 0.05 significance level. (Round your answers to 2 decimal places.)Hq is rejected if z is not between Compute the value of the test statistic. (Round your answer to 2 decimal places.) Value of the test statistic Does this data disagree with the Pet Food Dealers Association data? Use a 0.05 level of significance. Hq is rejected H. There is insufficient pevidence to show the proportion has changed. and.

Solution

Set Up Hypothesis
Null, H0:P=0.69
Alternate, H1: P!=0.69
Test Statistic
No. Of Success chances Observed (x)=235
Number of objects in a sample provided(n)=320
No. Of Success Rate ( P )= x/n = 0.7344
Success Probability ( Po )=0.69
Failure Probability ( Qo) = 0.31
we use Test Statistic (Z) for Single Proportion = P-Po/Sqrt(PoQo/n)
Zo=0.73438-0.69/(Sqrt(0.2139)/320)
Zo =1.7164
| Zo | =1.7164
Critical Value
The Value of |Z | at LOS 0.05% is 1.96
We got |Zo| =1.716 & | Z | =1.96
Make Decision
Hence Value of |Zo | < | Z | and Here we Do not Reject Ho
P-Value: Two Tailed ( double the one tail ) - Ha : ( P != 1.71636 ) = 0.0861
Hence Value of P0.05 < 0.0861,Here We Do not Reject Ho

[ANSWERS]
1. H0:P=0.69 , H1: P!=0.69
2. Reject Ho when Zo < - 1.96 AND Zo>1.96
3. Zo =1.7164
4. Do not Reject Ho, insuffcient