Find a basis of the row space of the matrix 0 2 4 1 8 2 14 2

Find a basis of the row space of the matrix

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$\"\\left.\\vphantom{\\begin{array}{c}\\!\\strut\\\\\\!\\strut\\\\\\!\\strut\\\\\\!\\strut\\\\\\end{array}}\$	0	-2	4	-1	$\"\\left.\\vphantom{\\begin{array}{c}\\!\\strut\\\\\\!\\strut\\\\\\!\\strut\\\\\\!\\strut\\\\\\end{array}}\$
8	-2	-14	2
-4	3	3	0

Step 1: Swapping R₂ with R₁:

Step 2: Add (1/2 * R₁) to R₃:

Step 3: Add R₂ to R₃:

Because we have found pivots in columns 0 and 1.

Therefore, the Column Space is given by the following equation:

A *

+B *

where A and B are any real numbers.