Ask the user for a base float and a positive exponent int Ca

Ask the user for a base (float) and a positive exponent (int). Calculate the base raised to the power of the exponent using a loop. For example:

Use the following format specifiers to get the precision to match the answers:

Solution

#include <iostream>
using namespace std;

int main()
{
   float result =1;
   int i;
   float base;
   int exponent;
   cout<<\"\ Please enter the base:\";
   cin>>base;
cout<<\"\ Please enter the exponent:\";
   cin>>exponent;
  
   for(i=1;i<=exponent;i++)   
   {
       result=result*base; //result=base*base*base*...... exponent times
   }
  
   cout.setf(ios::fixed, ios::floatfield); //format specifier
cout.precision(2);

   cout<<\"\ The answer is :\"<<result;
   return 0;
}

output:

Please enter the base:2

Please enter the exponent:3

The answer is :8.00