Simplify the next function F x yz xz F x yz F x yz F

Simplify the next function: F = (x + y\'z)+ xz F = x + y\'z F = x - y\'z F = x + yz F = x + z Simplify the next function: F = ((x + y)z)\' + (yz)\' + x\'

Solution

question 5:

the answer is a F=x+y\'z

The solution is as follows:

F=(x+y\'z)+xz

=x+y\'z+xz

=x+xz+y\'z rearranging the terms

=x(1+z)+y\'z Taking x common

=x+y\'z 1+z=1

Hence proved