Use the quadratic formula to solve for x 2x23x70SolutionQuad

Use the quadratic formula to solve for x

2x^2-3x-7=0

Quadratice formula for ax^2 +bx +c =0

x = (-b +/- sqrt(b^2 -4ac)/2a

we have 2x^2-3x-7=0

a = 2; b= -3 ; c = -7

So ,plugging all values : x= ( -2 +/- sqrt( 9 +7*2*4)/4

= ( -2 +/- sqrt65)/4

x = -1/2 + /- sqrt(65)/4 ( Solution)