For question 24 M is the midpoint of segment NP Use the foll

For question 24, M is the midpoint of segment NP. Use the following coordinates: N (-2,4) and M 24. Find the coordinates oflP Assume ZA and LB are complementary and ZB and LC are supplementary to answer the following questions and mLC = 26. Draw a segment. Then, copy it and find its perpendicular bisector. Identify the midpoint as point M in your construction 27. Draw an obtuse angle. Then, copy and bisect it. Identify the angle bisector as B2

Solution

24) Midpoint M(xo,yo) = [(x1 + x2)/2 , (y1 + y2)/2 ]

where (x1,y1) & (x2,y2) are coordinates of N & P respectively.

Then. (-1,0) = [ (-2+x2)/2, (4+y2)/2 ]

-1 = (-2+x2)/2. &. 0 =(4+y2)/2

x2 = 0. & y2 = -4

Therefore P = (0,-4)

25) A and B are complementary means A + B = 90

28 + B = 90

B= 62

B and C are supplementary means B + C = 180

62 + C = 180

C = 118