Determine the point estimate of the population proportion an

Determine the point estimate of the population proportion and the margin of error for the given confidence interval. Lower bound: 0201. upper bound: 0.249, n - 1200 Given the sample size n = 49, population parameter a = 28 find A random sample of 1003 adults Americans was asked \"Do you pretty much think televisions are a necessity or luxury you could do without ? Of 1003 adults surveyed. 521 indicated that televisions are a luxury they could do without. Construct a 95% confidence interval for the population proportion of adult American who believe that television arc a they could do without. Determine the null and alternative hypothesis

Solution

Q1.
Margin of Error = (Upper-Lower)/2 = (0.249-0.201)/2 = 0.024
Point of estimate = Lower + Margin of Error = 0.201 + 0.024 = 0.225

Q2.
Standard Deviation= sd/ Sqrt(n)
Where,
sd = Standard Deviation
n = Sample Size

Standard deviation( sd )=28
Sample Size(n)=49
Standard Error = ( 28/ Sqrt ( 49) )
= 4