X1X2X3 are iid random variables each with uniform01 distribu

X1,X2,X3 are i.i.d. random variables each with uniform(0,1) distribution. Find the pdf for the following random variables:

W1 = max(X1,X2,X3),
W2 = min(X1,X2,X3),
W3 = median(X1,X2,X3)

Solution

W1 = max(X1,X2,X3)

so pdf of w1

= P(W1<x)

= P( X1<x and X2<x and X3<x)

= P(X1<x)^3

= x^3

W2 = min(X1,X2,X3)

so, pdf

= P(W2<x)

= P(X1>x and X2>x ad X3>x)

= P(X1>x)^3

= (1-P(X1<x)^3

= (1-x)^3

W3 = median (X1,X2,X3)

median is the middle element, it can be X1 or X2 or X3 with equal probability

hence pdf of W3 = 1/3

X1,X2,X3 are i.i.d. random variables each with uniform(0,1) distribution. Find the pdf for the following random variables: W1 = max(X1,X2,X3), W2 = min(X1,X2,X3

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