Write in all assumptions and look upsSolutiontotal heat tran

Write in all assumptions and look ups.

Solution

total heat transfer Q = m*C_p*(T₁-T₂) = 0.1*1900*(373-333) = 7.6 KJ/s = 7.6 KW

these much of heat should be taken by water in ideal conditions.

So, Q = m*C_p*(T₁-T₂)

0.1*4200*(T₂-303) = 7600 hence T₂= 321 K = 48 C

Tm = (T1 – t2) – (T2 – t1) / ln (T1 – t2)/(T2 – t1)

A = Q / (U . Tm) = 7600 / (60*40) =3.16 m²

now assuming only single tube. n=1

hence A= Pi*D*L

L=A/(Pi*D) = 3.16/(3.14*0.025) = 40.254 m

L=A/(Pi*D) = 3.16/(3.14*0.040) = 25.19 m