Using a viable cell density of 1545X106 cellsml a determine

Using a viable cell density of 1.545X10^6 cells/ml, a) determine the required volume of the cell suspension needed to transfer 500,000 cells back to a fresh T-25 flask and b) determine the number of cells transferred to a fresh T-25 flask based on the volume of cell suspension added

Solution

a) the required volume of cell suspension needed to transfer 500,000 cells is

(500,000/1.545X10^6) which is equal to 0.32362 ml which is also equal to 323.62 micro liters.

b) If, 0.32362 ml of cell suspension is added back to a fresh T-25 flask, then the number of cells being transfered will be 500,000 (0.32362*1.545X10^6).