Solve the following system by the method of your choice x3y0

Solve the following system by the method of your choice.

x^3+y=0

3x^2-y=0

(Type an ordered pair. Use a comma to separate answers as needed. Type exact answers, using radicals as needed. Simplify your answer.)

x^3+y=0 ----(1)

3x^2-y=0 ----(2)

from equa : y = 3x^2

So, x^3 +3x^2 =0

x^2(x+3) =0

x=0 ; x=-3

substitute value of x to get value of y:

y = 3x^2 = 0

y = 3(-3)^2 = 27

Ordered pair (0,0) and (-3, 27)