Please answer all aspects of this question to the best of yo

Please answer all aspects of this question to the best of your knowledge. Those who answer neatly and ON PAPER will be given a preferential ratting.

Each of the electrons in the beam of a television tube has a kinetic energy of 16.0 keV. The tube is oriented so that the electrons move horizontally from north to south. The vertical component of Earth\'s magnetic field points down and has a magnitude o 46.0 Ignore the northward con one to Earth s e d /1n what direction wil the elec ron beam deflect? O up down north east west south Submit Answer Answer Submitted: Your final submission will be graded after the due date. Tries 1/16 Previous Tries Calculate the acceleration of a single electron due to the Earth\'s magnetic field Submit Answer Tries 0/32 How far will the beam deflect if it moves a distance of 19.0 cm to the south through the television tube? 750 cm The electron\'s motion is technically circular, but you can assume the acceleration is constant (in the same direction) if it makes your calculation easier Submit Answer Incorrect. Tries 4/16 Previous Tries

Solution

1.

South is the answer

From Right Hand rule, the fingers of the right hand should be oriented downward i.e along the direction of magnetic field B  with the thumb pointing to the east i.e along the direction of the velocity. The palm of the right hand points due north along the direction of force. Since the electron is negatively charged, it will be deflected due South

b)

From Newton\'s 2^nd law ,ELectric force is balanced by magnetic force

ma =qvBsin(o)

=>a=qvBsin(o)/m

Since Kinetic energy

KE=(1/2)mV²

=>V=sqrt[2*KE/m]=sqrt[2*(16*10³*1.6*10^-19)/(9.11*10^-31)]

V=7.5*10⁷ m/s

=>a =(1.6*10^-19)*(7.5*10⁷)(46*10^-6)sin90/(9.11*10^-31)

a=6.05*10¹⁴ m/s²

c)

The Time taken to travel 19 cm is

t=0.19/7.5*10⁷=2.53*10^-9 s

Beam Deflection

S=(1/2)at² = (1/2)*(6.05*10¹⁴)(2.53*10^-9)²

S=1.94*10^-3 m or 1.94 mm