Find the exact value in radian measure of each of the follow
Find the exact value, in radian measure, of each of the following: sin^-1 (- 1/2) arccos (- 1/Squareroot 2)
Solution
sin2x = tanx(1 +cos2x)
RHS : tanx(1 +cos2x) = tanx(2cos^2x)
= (sinx/cosx)(2cos^2x)
= 2sinx*cosx
= sin2x = LHS
6a) y = sin^-1(-1/2)
Range of sin^-1x : [ -pi/2 , pi/2]
So, siny = -1/2
y = -pi/6
b) y = arccos(-1/sqrt2)
Range of cos^-1x : [ 0 , pi]
cosy = -1/sqrt2
y = pi -pi/4 = 3pi/4
