Find the dimensions of a rectangle whose length is a foot lo

Find the dimensions of a rectangle whose length is a foot longer than twice its width and whose perimeter is 20 feet

Solution

Let length be L and breadth of the rectangle be B.

According to the question, we have:

L = 2B + 1 -----------------------------------------(1)

Also, perimeter is given as 20 feet so we get:

20 = 2(L + B) --------------------------------------(2)

Put equation (1) in equation (2), we get:

20 = 2(2B + 1 + B)

20 = 2(3B + 1)

20 = 6B + 2

6B = 18

B = 6 foot

Using this in equation (1), we get:

L = 2B + 1

L = 2*6 + 1

L = 13 foot

Therefore, length of the rectangle is 13 foot or feet and breadth is 6 foot or feet.