Find the particular solution of the differential equation dy
Find the particular solution of the differential equation
dy/dx
= (x?2)^e?2y
satisfying the initial condition y(2)=ln(2).
dy/dx
= (x?2)^e?2y
satisfying the initial condition y(2)=ln(2).
Solution
Find the particular solution of the differential equation
dy/dx
= (x2)^e2y
dy e^2y = dx (x-2)^2
e^2y/2 = (x-2)^3/3 + C
y(2)=ln(2).
e^ln4/2 = (2-2)^3/3 + C
4/2 = C
C = 2
e^2y/2 = (x-2)^3/3 + 2
